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x^2-33x=-90
We move all terms to the left:
x^2-33x-(-90)=0
We add all the numbers together, and all the variables
x^2-33x+90=0
a = 1; b = -33; c = +90;
Δ = b2-4ac
Δ = -332-4·1·90
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-27}{2*1}=\frac{6}{2} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+27}{2*1}=\frac{60}{2} =30 $
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